Concepts
Algebraic combinations of functions, composition, and decomposition of functions.
Algebraic Combinations of Functions
An ambitious way of creating new functions is to combine two or more functions to create a new function. The most obvious way we can do this is to perform basic algebraic operations on the two functions to create the new one; hence we can add, subtract, multiply, or divide functions.
Note that there are two types of algebras in use in this section:
- The algebra of real numbers, e.g.,
4 × 5 = 20, 4 − 5 = −1, 20/10 = 2, etc. - The algebra of functions, e.g.,
f + g, f − g, etc.
Algebra of Functions
Let f (with domain A) and g (with domain B) be functions. Then the functions f + g, f − g, fg, f / g are defined as:
(f + g)(x) = f(x) + g(x), domain: A ∩ B
(f − g)(x) = f(x) − g(x), domain: A ∩ B
(fg)(x) = f(x) * g(x), domain: A ∩ B
(f/g)(x) = f(x) / g(x), domain: {x ∈ A ∩ B | g(x) ≠ 0}
The domains are the intersection of the domains of f and g, ensuring that division by zero does not occur.
A Closer Look
- The minus sign in
f − grepresents the difference between two functions. - The minus sign in
f(x) − g(x)represents the difference between two real numbers.
The relation (f − g)(x) = f(x) − g(x) allows us to calculate this quantity, which is easy to remember. Understanding mathematical notation is key.
Note: Two functions are equal if they have the same functional definition and the same domain.
Example
If f(x) = √x and g(x) = √(4 − x²), find f + g, f − g, fg, f / g and their domains.
Domain of f = [0, ∞)
Domain of g = [−2, 2]
Intersection: [0, 2]
(f + g)(x) = √x + √(4 − x²), 0 ≤ x ≤ 2
(f − g)(x) = √x − √(4 − x²), 0 ≤ x ≤ 2
(fg)(x) = √x √(4 − x²) , 0 ≤ x ≤ 2
(f/g)(x) = √x / √(4 − x²), 0 ≤ x < 2
Important Note:
For (f/g)(x) we exclude x = 2 since it would lead to division by zero. Divide by Zero is undefined.
Composition of Functions
Given two functions f and g, the composite function f ◦ g is defined as:
(f ◦ g)(x) = f(g(x))
The domain of f ◦ g includes all x-values in the domain of g that map to values of g(x) in the domain of f. Note that f ◦ g ≠ g ◦ f.
Example
If f(x) = √x and g(x) = √(4 − x²), find f ◦ g and g ◦ f and their domains.
(f ◦ g)(x) = √(√(4 − x²))
Domain: [−2, 2]
(g ◦ f)(x) = √(4 − √x²)
Domain: [0, 2]
Important Note:
It is important to note that f ◦ g ≠ g ◦ f.
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